Vba controlla se i bit specifici sono impostati in int32
Esempi di codice
vba controlla se i bit specifici sono impostati in int32
'Fast VBA function to test if specific bits are set
'within a 32-bit Long integer. If ALL specified bits are set then
'this function returns True. If ANY of the specified bits are
'not set then this function returns False.
'Bits are numbered from 0 to 31, so the first (least significant) bit
'is bit 0.
'Note: bits can be specified in any order.
'Note: any number of bits can be specified in one call.
Function LongBitsAreSet(theLong&, ParamArray bits()) As Boolean
Static i&, b&()
If UBound(bits) = -1 Then Exit Function
If (Not Not b) = 0 Then
ReDim b(0 To 30)
For i = 0 To 30
b(i) = 2 ^ i
Next
End If
For i = 0 To UBound(bits)
If bits(i) < 0 Then Exit Function
If bits(i) > 30 Then Exit Function
If (theLong And b(Int(bits(i)))) = 0 Then Exit Function
Next
LongBitsAreSet = True
End Function
'---------------------------------------------------------------------------------------------------------------------
MsgBox LongBitsAreSet(255, 7) '<--displays: True 255 = 00000000 00000000 00000000 11111111
MsgBox LongBitsAreSet(230, 0) '<--displays: False 230 = 00000000 00000000 00000000 11100110
MsgBox LongBitsAreSet(85, 0, 2, 6, 4) '<--displays: True 85 = 00000000 00000000 00000000 01010101
MsgBox LongBitsAreSet(85, 0, 2, 5, 4) '<--displays: False 85 = 00000000 00000000 00000000 01010101
MsgBox LongBitsAreSet(485, 2, 7, 5) '<--displays: True 485 = 00000000 00000000 00000001 11100101
MsgBox LongBitsAreSet(24585, 14, 13, 3) '<--displays: True 24585 = 00000000 00000000 01100000 00001001
MsgBox LongBitsAreSet(&H7D12EACB, 24, 26, 30, 7) '<--displays: True 2098391755 = 01111101 00010010 11101010 11001011
'
'
'
excel vba sono bit impostati in byte
'Fast VBA function to test if specific bits are set
'within a Byte. If ALL specified bits are set then this function
'returns True. If ANY of the specified bits are not set then
'this function returns False.
'Bits are numbered from 0 to 7, so the first (least significant) bit
'is bit 0.
'Note: bits can be specified in any order.
Function ByteBitsAreSet(theByte As Byte, ParamArray bits()) As Boolean
Static i&, b() As Byte
If UBound(bits) = -1 Then Exit Function
If (Not Not b) = 0 Then
ReDim b(0 To 7)
For i = 0 To 7
b(i) = 2 ^ i
Next
End If
For i = 0 To UBound(bits)
If bits(i) < 0 Then Exit Function
If bits(i) > 7 Then Exit Function
If (theByte And b(Int(bits(i)))) = 0 Then Exit Function
Next
ByteBitsAreSet = True
End Function
'--------------------------------------------------------------------------
MsgBox ByteBitsAreSet(255, 7) '<--displays: True 255 = 11111111
MsgBox ByteBitsAreSet(230, 0) '<--displays: False 230 = 11100110
MsgBox ByteBitsAreSet(85, 0, 2, 6, 4) '<--displays: True 85 = 01010101
MsgBox ByteBitsAreSet(85, 0, 2, 5, 4) '<--displays: False 85 = 01010101
'
'
'
excel vba imposta bit in byte
'Extremely fast VBA function to test if a specified bit is set
'within a Byte.
'Bits are numbered from 0 to 7, so the first (least significant) bit
'is bit 0.
Function ByteBitIsSet(theByte As Byte, bit As Byte) As Boolean
Static i&, b() As Byte
If (Not Not b) = 0 Then
ReDim b(0 To 7)
For i = 0 To 7
b(i) = 2 ^ i
Next
End If
If bit < 8 Then ByteBitIsSet = theByte And b(bit)
End Function
'------------------------------------------------------------------
MsgBox ByteBitIsSet(255, 7) '<--displays: True
MsgBox ByteBitIsSet(230, 0) '<--displays: False
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