Vba controlla se i bit specifici sono impostati in int32 excel
Esempi di codice
xl vba è un bit specifico impostato in longlong integer
'Extremely fast VBA function to test if a specified bit is set
'within a 64-bit LongLong integer.
'Bits are numbered from 0 to 63, so the first (least significant) bit
'is bit 0.
'Note: we do not inspect bit 63, the sign bit.
'Note: the LongLong data type is only available in 64-bit VBA.
Function LongLongBitIsSet(theLongLong^, bit As Byte) As Boolean
Static i&, b^()
If (Not Not b) = 0 Then
ReDim b(0 To 62)
For i = 0 To 62
b(i) = 2 ^ i
Next
End If
If bit < 63 Then LongLongBitIsSet = theLongLong And b(bit)
End Function
'------------------------------------------------------------------
MsgBox LongBitIsSet(255, 7) '<--displays: True
MsgBox LongBitIsSet(230, 0) '<--displays: False
MsgBox LongBitIsSet(16384, 14) '<--displays: True
MsgBox LongBitIsSet(-16383, 0) '<--displays: True
MsgBox LongBitIsSet(&H7FFFFFFF, 0), 0) '<--displays: True
MsgBox LongLongBitIsSet(&H7FFFFFFFFFFFFFff^, 62) '<--displays: True
'
'
'
vba controlla se i bit specifici sono impostati in int32 excel
'Fast VBA function to test if specific bits are set
'within a 32-bit Long integer. If ALL specified bits are set then
'this function returns True. If ANY of the specified bits are
'not set then this function returns False.
'Bits are numbered from 0 to 31, so the first (least significant) bit
'is bit 0.
'Note: bits can be specified in any order.
'Note: any number of bits can be specified in one call.
Function LongBitsAreSet(theLong&, ParamArray bits()) As Boolean
Static i&, b&()
If UBound(bits) = -1 Then Exit Function
If (Not Not b) = 0 Then
ReDim b(0 To 30)
For i = 0 To 30
b(i) = 2 ^ i
Next
End If
For i = 0 To UBound(bits)
If bits(i) < 0 Then Exit Function
If bits(i) > 30 Then Exit Function
If (theLong And b(Int(bits(i)))) = 0 Then Exit Function
Next
LongBitsAreSet = True
End Function
'---------------------------------------------------------------------------------------------------------------------
MsgBox LongBitsAreSet(255, 7) '<--displays: True 255 = 00000000 00000000 00000000 11111111
MsgBox LongBitsAreSet(230, 0) '<--displays: False 230 = 00000000 00000000 00000000 11100110
MsgBox LongBitsAreSet(85, 0, 2, 6, 4) '<--displays: True 85 = 00000000 00000000 00000000 01010101
MsgBox LongBitsAreSet(85, 0, 2, 5, 4) '<--displays: False 85 = 00000000 00000000 00000000 01010101
MsgBox LongBitsAreSet(485, 2, 7, 5) '<--displays: True 485 = 00000000 00000000 00000001 11100101
MsgBox LongBitsAreSet(24585, 14, 13, 3) '<--displays: True 24585 = 00000000 00000000 01100000 00001001
MsgBox LongBitsAreSet(&H7D12EACB, 24, 26, 30, 7) '<--displays: True 2098391755 = 01111101 00010010 11101010 11001011
'
'
'
excel vba controlla se il bit è impostato in integer
'Extremely fast VBA function to test if a specified bit is set
'within a 16-bit Integer.
'Bits are numbered from 0 to 15, so the first (least significant) bit
'is bit 0.
'Note: we do not inspect bit 15, the sign bit.
Function IntegerBitIsSet(theInteger%, bit As Byte) As Boolean
Static i&, b%()
If (Not Not b) = 0 Then
ReDim b(0 To 14)
For i = 0 To 14
b(i) = 2 ^ i
Next
End If
If bit < 15 Then IntegerBitIsSet = theInteger And b(bit)
End Function
'------------------------------------------------------------------
MsgBox IntegerBitIsSet(255, 7) '<--displays: True
MsgBox IntegerBitIsSet(230, 0) '<--displays: False
MsgBox IntegerBitIsSet(16384, 14) '<--displays: True
MsgBox IntegerBitIsSet(-16383, 0) '<--displays: True
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